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What Math Equations Look Like in 3-D (wired.com)
36 points by fahrbach on June 26, 2014 | hide | past | favorite | 5 comments


"It’s one thing to check that the derivatives of a function are zero and another to feel the plaster taper to a sharp point."

Those are two very different things. A sharp point is not differentiable. A derivative of zero indicates a possible minimum or maximum of the function.


No, they are the same thing. What this sentence is referring to is the vanishing of the Jacobian determinant [1] (which is defined using the derivatives of the defining equations).

A simple example is the equations y^3 - x^2 = 0. This is a "cusp" (use wolfram alpha to see what it looks like) and has a singularity at the origin.

The jacobian is the matrix:

[ -2x, 3y^2 ]

This has rank 1 unless x and y are zero in which case it has rank zero. The fact that the rank is less than 1 indicates a singularity.

[1]: http://en.wikipedia.org/wiki/Singularity_(mathematics)#Algeb...


This seems to explain the sentence. Thank you, now I have something to read about for the next few hours.


In a parametric curve, a derivative of zero may indicate a cusp, which I feel is where the comparison is coming from.

I only read your comment and article but didn't see the video, so this comment may be off.


Fixed headline: "This is what 3d graphs of math equations look like".




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