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Just a small fix for those that were checking as I was

If the ground distance each way is D, airspeed is V, and wind speed relative to the ground is w, total time is D/(V-w) + D/(V+w) = 2DV/(V^2-w^2) = 2D/((V^2-w^2)/V).

For 0 < w < V: this is more than the 0 wind case. For w >= V: the headwind is so high that you can't make any progress toward the destination).

The last result being somehow obvious ;)



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