No it's not. The factoring problem/RSA problem have never been proven to be NP-complete. Shor's algorithm shows that it's NP, but not NP-complete (or hard). I think it's also in co-NP.
Yeah.... but like he said, RSA being in P does not imply that P=NP because RSA has not be shown (and isn't believed) to be NP-complete. If P=NP, then RSA would of course be in P.
